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Fizz Buzz

Published at24 Jul 2026
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TypeScript Data Structures Medium 0 views
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Write a TypeScript function that returns an array of strings from 1 to n. For multiples of 3, store 'Fizz' instead of the number. For multiples of 5, store 'Buzz'. For multiples of both 3 and 5, store 'FizzBuzz'.

Initialize an empty array. Loop from 1 to n. Use conditionals with the modulo operator to check divisibility. Push the appropriate string to the array based on the conditions.

The order of conditions matters: check for FizzBuzz (multiple of 15) first since numbers like 15 are multiples of both 3 and 5. If you check Fizz first, you would incorrectly output 'Fizz' for 15 instead of 'FizzBuzz'.

Edge cases include n = 0 (return empty array), n = 1 (return ['1']), and n = 15 (contains FizzBuzz at position 15). The function uses a for loop with string array building and the push() method.

FizzBuzz is a classic programming interview question that tests basic control flow and modulo arithmetic. TypeScript's type annotations document the function signature clearly, making the code self-documenting with the return type string[].

The modulo operator % returns the remainder of division. If i % 15 === 0, i is divisible by both 3 and 5, so it's a FizzBuzz number. The strict equality operator === ensures type-safe comparison without coercion.

Example Input & Output

Example 1
Input
1
Output
["1"]
Example 2
Input
5
Output
["1","2","Fizz","4","Buzz"]
Example 3
Input
0
Output
[]
Example 4
Input
15
Output
["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
Example 5
Input
3
Output
["1","2","Fizz"]

Algorithm Flow

Recommendation Algorithm Flow for Fizz Buzz
Recommendation Algorithm Flow for Fizz Buzz

Solution Approach

Write a TypeScript function that returns an array of strings from 1 to n. For multiples of 3, store 'Fizz' instead of the number. For multiples of 5, store 'Buzz'. For multiples of both 3 and 5, store 'FizzBuzz'.

Initialize an empty array. Loop from 1 to n. Use conditionals with the modulo operator to check divisibility. Push the appropriate string to the array based on the conditions.

The order of conditions matters: check for FizzBuzz (multiple of 15) first since numbers like 15 are multiples of both 3 and 5. If you check Fizz first, you would incorrectly output 'Fizz' for 15 instead of 'FizzBuzz'.

Edge cases include n = 0 (return empty array), n = 1 (return ['1']), and n = 15 (contains FizzBuzz at position 15). The function uses a for loop with string array building and the push() method.

FizzBuzz is a classic programming interview question that tests basic control flow and modulo arithmetic. TypeScript's type annotations document the function signature clearly, making the code self-documenting with the return type string[].

The modulo operator % returns the remainder of division. If i % 15 === 0, i is divisible by both 3 and 5, so it's a FizzBuzz number. The strict equality operator === ensures type-safe comparison without coercion.

Best Answers

typescript - Approach 1
function fizzBuzz(n: number): string[] {
    var result: string[] = [];
    for (var i = 1; i <= n; i++) {
        if (i % 15 === 0) result.push('FizzBuzz');
        else if (i % 3 === 0) result.push('Fizz');
        else if (i % 5 === 0) result.push('Buzz');
        else result.push(String(i));
    }
    return result;
}